3x(5-x)+(x+)^2=-6x+7

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Solution for 3x(5-x)+(x+)^2=-6x+7 equation: 



3x(5-x)+(x+)^2=-6x+7

We move all terms to the left:

3x(5-x)+(x+)^2-(-6x+7)=0

We add all the numbers together, and all the variables

3x(-1x+5)+(+x)^2-(-6x+7)=0

We multiply parentheses

-3x^2+15x+(+x)^2-(-6x+7)=0

We get rid of parentheses

-3x^2+15x+(+x)^2+6x-7=0

We add all the numbers together, and all the variables

-3x^2+21x+(+x)^2-7=0

We move all terms containing x to the left, all other terms to the right

-3x^2+21x+(+x)^2=7

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